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向量几何 / 1 OF 5

余弦近邻

A large document norm should not dominate cosine ranking.

本地计算 / 模拟

本地教学实验,不调用外部 API。合成示例不能替代生产环境测量。

学习指南与本课目录LEARNING CONTRACT

理解 → 实现 → 研究

目标:解释本课机制、复现一个例子、测试一个失败案例。读完不自动代表掌握。

02 · 预测与配置

技术场景说明、参数名称与参考答案目前为英文。

03 · 检查证据

运行实验后查看结果。

方法与参考资料

Five manually chosen 2D vectors, not embeddings generated by a language model. Zero-vector cosine is defined as 0 in this lab. Ties preserve fixture order.

Text / 原始公式
cos(q,d)=q·d/(||q|| ||d||); dot(q,d)=Σqᵢdᵢ

Geometry alone cannot establish semantic relevance; these vectors are hand-authored.

Introduction to Information Retrieval · vector space scoring ↗

练习题

embedding-1 / 01What does “Cosine nearest neighbors” test?

A large document norm should not dominate cosine ranking.

Original teaching answer / local derivation. Method reference: Introduction to Information Retrieval · vector space scoring ↗

打开实验 →
embedding-1 / 02Which computation produces the result in “Cosine nearest neighbors”?

·d/(||q|| ||d||);

Original teaching answer / local derivation. Method reference: Introduction to Information Retrieval · vector space scoring ↗

打开实验 →
embedding-1 / 03What is the baseline configuration for “Cosine nearest neighbors”?

{"x":1,"y":0.2,"metric":0}

Original teaching answer / local derivation. Method reference: Introduction to Information Retrieval · vector space scoring ↗

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embedding-1 / 04What numerical result should you check for “Cosine nearest neighbors”?

{"Top score":0.9999999999999998,"Query norm":1.019803902718557}

Original teaching answer / local derivation. Method reference: Introduction to Information Retrieval · vector space scoring ↗

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embedding-1 / 05How would you run a controlled comparison for “Cosine nearest neighbors”?

Keep the supplied fixture and other settings fixed; change x. Compare ranking order, vector norms and scores on identical documents.

Original teaching answer / local derivation. Method reference: Introduction to Information Retrieval · vector space scoring ↗

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embedding-1 / 06What failure could invalidate a conclusion from “Cosine nearest neighbors”?

Geometry alone cannot establish semantic relevance; these vectors are hand-authored.

Original teaching answer / local derivation. Method reference: Introduction to Information Retrieval · vector space scoring ↗

打开实验 →
embedding-1 / 07Is “Cosine nearest neighbors” a benchmark of a deployed language model?

No. Five manually chosen 2D vectors, not embeddings generated by a language model. Zero-vector cosine is defined as 0 in this lab. Ties preserve fixture order.

Original teaching answer / local derivation. Method reference: Introduction to Information Retrieval · vector space scoring ↗

打开实验 →
embedding-1 / 08Which evidence should you report for “Cosine nearest neighbors”?

Compare ranking order, vector norms and scores on identical documents. Export inputs, engine, result and method; distinguish synthetic fixtures from observed production data.

Original teaching answer / local derivation. Method reference: Introduction to Information Retrieval · vector space scoring ↗

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embedding-1 / 09How can another researcher reproduce “Cosine nearest neighbors”?

Open embedding-1, reset the preset, retain the exact inputs and run. The calculation is deterministic for identical inputs.

Original teaching answer / local derivation. Method reference: Introduction to Information Retrieval · vector space scoring ↗

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embedding-1 / 10What is the next validation step after “Cosine nearest neighbors”?

Geometry alone cannot establish semantic relevance; these vectors are hand-authored. Test the hypothesis on a representative held-out workload and document a baseline, success metric and stopping rule before claiming deployment readiness.

Original teaching answer / local derivation. Method reference: Introduction to Information Retrieval · vector space scoring ↗

打开实验 →
MATHEMATICAL REVIEW · 2026-10-26

假设、参考实现与验收

零向量的数学余弦未定义。程序返回零作为哨兵值,不能解读为正交。点积与余弦的尺度敏感性不同。

已复核引擎公式、场景预设及数值保护。固定种子的合成输入不是生产基准。

查询与文档向量 → 点积或归一化余弦 → 按分数排序 · 检查零向量 → 改变范数 · 比较排序
机制图:从上到下跟踪每次变换。

运行前:预测一个边界情况

A large document norm should not dominate cosine ranking.

提示:隔离假设

固定基线输入,只改变一个参数或边界;同时比较数值与声明单位。单例通过仅验证该样例。

最小可运行算例

将算例及所链接模块保存在同一目录。使用 Node.js 22 或更高版本,然后运行 node embedding-1.mjs. 无需第三方运行依赖。

import {calculate,network} from './academy-core.mjs';
const params={
  "x": 1,
  "y": 0.2,
  "metric": 0
};
const result=calculate('embedding',params);
console.log(result.metrics);

测试与迁移

A large document norm should not dominate cosine ranking.

在下方笔记记录输入、代码版本、期望值和实测值;再构造违反上述假设的反例,解释原结论为何不再成立。

下载完整代码包(.tar.gz) · 完整参考代码与回归检查

预测、检验与证据记录

展开答案前先预测一个结果;练习后记录差异和迁移测试。记录仅存本地,在不同语言版本间共用。

打开记录/导出/清除 →

数学复核范围逐篇记录,不代表完成论文实证复现;可在笔记中记录疑似错误。 复核范围